48x^2-96x+21=0

Solution for 48x^2-96x+21=0 equation:

48x^2-96x+21=0

a = 48; b = -96; c = +21;
Δ = b2-4ac
Δ = -962-4·48·21
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-72}{2*48}=\frac{24}{96}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+72}{2*48}=\frac{168}{96}
=1+3/4
$